A pig's face is represented with a big circle. Its snout is a small circle that passes through the center/centre of the big circle and is tangent to it.

A pig’s face is represented by a big circle. Its snout is represented by a small circle that passes through the centre/center of the big circle and is tangent to it. The perimeter of the pig’s snout is 6π6\pi.

What is the area of the pig’s face?

Solution

Let rr be the radius of the small circle. Then, the radius of the big circle is 2r2r.

As the perimeter of the small circle is 6π6\pi, we get:

2πr=6π2\pi r=6\pi
r=3r=3

Then, the radius of the big circle is 6.

So, the area of the pig’s face is

π(6)2\pi\left(6\right)^2
36π36\pi

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