Truncated cuboctahedron composed by twelve squares, eight regular hexagons and six regular octagons.

Polyhedron with twenty six faces: twelve squares, eight regular hexagons and six regular octagons. It has seventy-two edges and forty-eight vertices. It is a Archimedean solid as it is a convex uniform polyhedra composed of regular polygons meeting in identical vertices, excluding the five Platonic solids (which are composed of only one type of polygon) and excluding the prisms and antiprisms.

The surface area of a truncated cuboctahedron with edge length a is given by the formula:

\text{Surface area}=12 \left( 2 + \sqrt{2} + \sqrt{3} \right) a^2

The volume of a truncated cuboctahedron with edge length a is given by the formula:

\text{Volume}=\left( 22 + 14 \sqrt{2} \right) a^3

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