A pig's face is represented with a big circle. Its snout is a small circle that passes through the center/centre of the big circle and is tangent to it.

A pig’s face is represented by a big circle. Its snout is represented by a small circle that passes through the centre/center of the big circle and is tangent to it. The perimeter of the pig’s snout is 6π.

What is the area of the pig’s face?

Solution

Let r be the radius of the small circle. Then, the radius of the big circle is 2r.

As the perimeter of the small circle is 6π, we get

2\pi r=6\pi

r=3

Then, the radius of the big circle is 6.

So, the area of the pig’s face is

\pi\left(6\right)^2=36\pi

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