A truncated octahedron composed by eight regular hexagons and six squares.

Polyhedron with fourteen faces: eight regular hexagons and six squares. It has thirty six edges and twenty four vertices. It is a Archimedean solid as it is a convex uniform polyhedra composed of regular polygons meeting in identical vertices, excluding the five Platonic solids (which are composed of only one type of polygon) and excluding the prisms and antiprisms.

The surface area of a truncated octahedron with edge length a is given by the formula:

\text{Surface area}=\left(6+12 \sqrt{3} \right) a^2

The volume of a truncated octahedron with edge length a is given by the formula:

\text{Volume}=8\sqrt{2} a^3

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